| Q. | Laser light of 589 nm wavelength is shown through parallel slits? | Related Search:
Physics | | | Laser light of 589 nm wavelength is shown through parallel slits forming a series of maxima on a screen 4.20 m away. If the distance between the central maximum and the first order maximum is 1.67 cm, what is the slit separation?
| | A. | The formula for diffraction of light is λ = d sinθ / n
for
λ = wavelength of light
d = distance between slits
θ = angle produced by slits, from central to another measured maxima.
n = order number of maximum being used (in this case, one)
First we need θ.
Since the screen and laser are at right angles to one another, we have a right angle triangle. The two known sides are 0.0167 m (opposite side) and 4.20 m (adjacent side).
Therefore we can use tan-1 (0.0167/4.20) to find the angle θ.
This is 0.228 degrees. A small answer like this is expected due to the small ratio between the side lengths.
Now, we can rearrange the formula to get λ/sinθ = d (remember n = 1 so it doesn't matter in this case).
Now substitute the numbers in and you get 589x10^-9 m / sin(0.228) = 1.48 x 10^-4 m, which is your answer. If you would like to convert, this is 0.148 mm between slits. | | | |
| Q. | I got a class ranking of 3 out of 589 students, is that good enough for an ivy leage college? | Related Search:
Higher Education (University ) | | | well i got all a's in my honors classes and i got my transcript back. apparently i placed a 3 out of 589 freshman. im happy but i know some other people had the same exact gpa and placed a 3 as well. Is 3 good enough to get into someone where like Harvard or Duke? assuming my SAT and GPA are very high.
| | A. | Duke, probably. Not Harvard. My friend's brother had a 4.0 GPA and scored PERFECT (no im not exaggerating, he actually got perfect) on his SATs. he did not get into Harvard.
But....that is Harvard. Other ivy leauge schools u should have no problem getting in with. If I were u, id try my luck at University of Columbia......or Tuffs (if you are the artsy, creative, type) | | | |
| Q. | For 589 nm light, calculate the critical angle for total internal reflection in sodium chloride? | Related Search:
Physics | | | For 589 nm light, calculate the critical angle
for total internal reflection in sodium chloride
(index of refraction 1.544) surrounded by
linseed oil (index of refraction 1.48).
Answer in units of ◦.
| | A. | Here, sodium chloride (n = 1.544) is surrounded by linseed oil (n = 1.48).
For total internal reflection to occur, incident light from the sodium
chloride must first have an angle of refraction of 90°.
Setting n1 = 1.544 , θ1 = θc , n2 = 1.48 , and θ2 = 90° in the law of
refraction, we find that
.......... (1.544)*sin θc = (1.48)*sin 90° = 1.48
.......... sin θc = 1.48/1.544 = 0.958549
.......... θc = arcsin(0.958549) = 73.4° | | | |
| Q. | What is the best/fastest way to get into downtown Tampa from the Suncoast/589 to avoid the traffic clog? | Related Search:
Commuting | | | It gets clogged right after the last toll until reaching downtown exit on 275. Any good shortcuts? I'm new to town.
| | A. | sorry no i go the same way as you do.. | | | |
| Q. | What is the best math strategy to work out the problem: 666-589? | Related Search:
Primary & Secondary Education | | | Please don't use alge rhythem! Thanks!
| | A. | 589 is pretty close to 600, so 666 - 600 is really easy: 66
But 589 isn't 600, it's less. 600 - 589 is 11. So you needed to subtract MORE than 66: 11 more.
66 + 11 = 77 | | | |
| Q. | A 589 kg satellite is in a circular orbit about the Earth at a height above the Earth equal to the Earth's mea? | Related Search:
Physics | | | A 589 kg satellite is in a circular orbit about the Earth at a height above the Earth equal to the Earth's mean radius.
(a) Find the satellite's orbital speed.
__m/s
(b) Find the period of its revolution.
__h
(c) Find the gravitational force acting on it.
__N
| | A. | (A) Equate the centripetal acceleration with the gravitational.
Re = radius of the Earth
G = gravitational constant
M = mass of the Earth
Gravitational: g = GM/r^2
Centripetal: a = v^2/r
GM/r^2 = v^2/r
v^2 = GM/r
v = SQRT[GM/r]
For this problem we have r = 2*Re
v = SQRT[GM/(2*Re)]
(B) Period can be found by dividing the circumference of the orbit by the orbital speed.
Circumference = C = 2*pi*(2*Re) = 4*pi*Re
Period = 4*pi*Re/v
(C) Just use the standard formula.
Force = GMm/(2*Re)^2
Force = GMm/(4*Re^2)
I will leave the details of the calculations for you to carry out. If you do not have the appropriate values for G, M, Re, then a simple search will find them. If you use the standard values then the units for speed will be m/s and force will be in Newtons. Period, however, will be in seconds and must be converted to hours by dividing by 60*60 = 3600, the number of seconds in a hour.
NOTE. And what should I look for in my mailbox? I see no email from you if that is what you are talking about. If you did send an email you might want to resend it since sometimes email disappears and sometimes emails are not delivered in a reasonable amount of time. | | | |
| Q. | How do I express 46,589.03365 with only 3 significant figures? | Related Search:
Mathematics | | | the problem used a measurement of 39.0. That's 3 significant figures right? So how do I express 46,589.03365 with only 3 significant figures?
| | A. | 46,600.00000
39.0 can be 2 sig. fig. or it could be 3 sig. fig. | | | |
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