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Q.When I originally did my fafsa I put all 0s for my moms ss#. What can I do?Related Search:
Financial Aid
 I thought I could go back and make corrections but it says I can only do that if it's processed (which it can't be processed now bc she hasn't signed electronically). It says it's missing my parents pin# which isn't working w/her real ss# or all 0s as the ss#. I tried to start completely over but it isn't working. What is the problem and what do I have to do now?
A.I had a student run into a similar problem today. We called the FAFSA hotline for assistance. 1-800-4-FED-AID (1-800-433-3243) or 1-319-337-5665 It sounds like you had not actually submitted the FAFSA yet, only saved it. Try going in under the link "Continue working on a saved FAFSA". You will need to remember the password you gave for yourself. Another option might be to go into "Fill out a Renewal FAFSA" which will import some of you information from a previous FAFSA. The zeros may have really confused the computer.
  

Q.Would you support incorporating the years 0 BC and 0 AD into the calendar?Related Search:
Other - Society & Culture
 That way, the way we speak of centuries and decades (1900s, 20s) would match up with the ordinal values (20th century, 3rd decade) since for example the 20th century and 1900s are currently two different things (1901-2000 vs. 1900-1999). The conversion is simple. 100 BC...3 BC, 2 BC, 1 BC becomes 98 BCA...1 BCA, 0 BCA, 0 AD So you just subtract 2 to go from BC to BCA (BC-adjusted) Add 2 to go from BCA to BC In that way we have: ... 2nd century BCA = (199 BCA-100 BCA) = the 100s BCA 1st century BCA = (99 BCA-0 BCA) = the 0s BCA 1st century ADA = (0 AD-99 AD) = the 0s ADA 2nd century ADA = (100 AD-199 AD) = the 100s ADA ... Works great on a time line too. And people will stop getting the beginnings and ends of centuries and millenniums wrong. Also, if you could give your reason as to why or why not you would or would not support this, I would appreciate it.
A.No. It's already been changed to CE (common era) and BCE (before common era) in most academic language anyway.
  

Q.Why aren't zip disks examples of optical stoage?Related Search:
Other - Computers
 bc they can hold megabytes of data? they use magnetized film to record 1s and 0s? They are not roung and shiny? They are thicket than floppy disks?
A.Because they are magnetic and read by magnets rather than being read by lasers (like CDs, DVDs, etc.)
  

Q.Physics question?Related Search:
Physics
 A.B.C are three points on a straight road such that A.B = 80m and BC= 60m. A car travelling with uniform acceleration passes ABC at times t=0s t=4s t=6s respectively, acceleration and velocity at A would be? please show and explain working
A.uniform acceleration: x(t) = 1/2 at^2 + v0 t + x0 x(0) = 0 x(4) = 80 meters x(6) = 140 meters The first equation gives you x0 = 0. 80m = 1/2 a (4s)^2 + v0 (4s) 140m = 1/2 a (6s)^2 + v0 (6s) Two equations, two unknowns. Do some algebra to solve for acceleration (a) and v0, the initial velocity at A.
  

Q.Kinematics of a particle-workings of questions please?Related Search:
Mathematics
 1)The brakes of a train can produce a retardation of 1.7m/s². Train is travelling at 100km/h and applies its brakes, what distance does it travel before stopping. Any one know the working out? I got 2.27 when the answer is 227m. I attempted to convert it into m/s by 100*100/60*60. 2)A B C are 3 points on a straight road. AB=80m BC=60m. A car travelling with uniform acceleration passes A, B, C at times t=0s t=4s t=6s respectively. Modelling the car a particle, find its acceleration and its velocity at A.
A.1) s = (v^2 - 0) / (2a) s = ([(100 km/h)(1,000 m/km)(1 h/3,600 s)]^2 - 0) / (2(1.7 m/s^2)) s ≈ ([(250 m)/(9 s)]^2 ) / (3.4 m/s^2) s ≈ (62,500 m^2)/(81 s^2)] / (3.4 m/s^2) s ≈ (62,500 m) / 275.4 s ≈ 226.9426 m ≈ 227 m 2) Vo(4 s) + (1/2)a(4 s)^2 = 80 m Vo(6 s) + (1/2)a(6 s)^2 = 140 m Vo(4 s) + a(8 s) = 80 m Vo(6 s) + a(18 s) = 140 m Vo + (2 s)a = 20 m/s 3Vo + (9 s)a = 140 m/s Vo = 20 m/s - (2 s)a 3(20 m/s - (2 s)a) + (9 s)a = 140 m/s 60 m/s - (6 s)a + (9 s)a = 140 m/s (3 s)a = 80 m/s a = (80/3) m/s^2 Vo = 20 m/s - (2 s)(80/3) m/s^2 Vo = 20 m/s - (160/3) m/s Vo = - (100/3) m/s I think you might have the values for AB and BC reversed.
  

Q.A suvat A-level mechanics and maths problem I am stuck on, can anyone help?Related Search:
Mathematics
 The question is as follows: A,B and C are three points on a straight road such that AB = 80m and BC = 60m. A car travelling with uniform acceleration passes A,B and C at times t=0s, t=4s and t=6s respectively. Modelling the car as a particle find its acceleration and its velocity at A. I would appreciate some help on this question thanks, but you don't have to explain every single step in too much detail if you just roughly show me the steps I should pick it up (e.g. I know it involves a simultaneous equation). Thank you.
A.The car's average velocity over AB is 20 m/s. Its average velocity over BC is 30 m/s. Because its acceleration is constant, it should have been traveling at exactly these velocities at the mid-times of the intervals in which it covered those stretches. That is, its velocity at time t=2s was 20 m/s and its velocity at time t=5s was 30 m/s. From this, you can compute the acceleration, which being constant over the whole trip must also be the acceleration at time t=0s when it passes A. (I get 10/3 m/s².) And knowing the acceleration and the exact velocity two seconds later, you should be able to compute the velocity at A. (I get 40/3 m/s).
  

Q.kindly answer plxxx!!!about slopes!!!help?Related Search:
Mathematics
 distance 5|• •F/-50s 4|• •E/-40s 3|• •D-30s 2|• •C/-20s 1|• •B/-10s 0|••A/-0s ------------------------------ 0 10 20 30 40 50 time solve for the value of the edges of the slopes!!!! a.) BC b.) CD c.) DE answer it plxx!!! i need the answer!! its my homework!!
A.Your question is incomprehensible. Are you sure that YOU understand the question ? If you want to receive an answer you must state it in a clear, unambiguous form. The rest of us may be clever, but we're not psychic !
  
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Millennium: 1st millennium BC
Centuries: 2nd century BC1st century BC1st century
Decades: 30s BC 20s BC 10s BC0s BC0s 10s 20s
Years: BC BC BC BC BC BC BC BC BC
Categories: BirthsDeathsArchitecture
EstablishmentsDisestablishments

This article concerns the period 9 BC – 1 BC, the last nine years of the 1st century BC. Note that there is no year zero (0) in either the proleptic Gregorian calendar or Julian calendar. Hence 1 BC is followed by the year AD 1.

AD 1 is the first year of the Anno Domini era and of the Common Era. In 525 (the consulship of Probus Junior [Flavius Probus]), a Christian monk named Dionysius Exiguus stated that the incarnation of Jesus occurred 525 years earlier.[1] Whether Dionysius regarded "incarnation" as Jesus' birth or conception, and whether Dionysius placed it in 1 BC or AD 1 are debated by modern scholars. Nevertheless, these same scholars believe Jesus was actually born a few years earlier, during this decade.

Contents

[edit] Events and trends

[edit] Significant people

[edit] Births

Albrecht Altdorfer's painting the Adoration of the Magi (made ca. 1530) is one of several works of art concerning the Navity of Jesus. Though Jesus's exact birthdate is unknown (other than it would have occurred sometime during this decade), but what is certain is that his teachings would form the foundation of Christianity, which is today a major world religion with a following of around a third of the world's Population[3]

[edit] Deaths

[edit] References



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