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 Questions 'n' Answers about '0s' Opens New Window.

Q.How many 0s does a Googolplex have in it?Related Search:
Mathematics
 I know that a googol is a 1 followed by 100 0s, but how many would that put behind the 1 in the googolplex. I would assume it to be 10 billion times the googol. Anywho, someone clear this up a bit before I spontaneously combust...
A.googol: 10100, or 1 followed by 100 zeros googolplex: 10^10^100, or 10^googol, or 1 followed by a googol zeros
  

Q.How can I view a file's contents as a string of 1s and 0s?Related Search:
Programming & Design
 I'm writing a compression program, and I was wondering if there were any utilities that would let me view the contents of a file as a string of 1s and 0s (not hex, octal, or ASCII). I'm running an x32 flavor of Ubuntu.
A.Hex is almost the same as binary. Read in the hex, then convert it to binary yourself, it's not hard. Each hex character represents four bits.
  

Q.How many ternary strings that contain two consecutive 0s?Related Search:
Mathematics
 How many ternary strings that contain two consecutive 0s. What are the initial conditions(for recurrence relation)? How many ternary strings of length six contain two consecutive 0s?
A.Start with some data. Let n be the string length. n = 2: {00}, so 1 n = 3: {000, 001, 002, 100, 200}, so 5 n = 4: {0000, 0001, 0002, 1000, 2000, 0010, 0011, 0012, 0020, 0021, 0022, 1001, 1002, 2001, 2002, 0100, 0200, 1100, 1200, 2100, 2200}, so 21 Wait, let's count the opposite, ternary strings without 00. That means there are no 0's or the 0's are isolated. There are 3^n total ternary strings, so we can just subtract these. n = 1: {0, 1, 2}, so 3 n = 2: all except 00, so 8 n = 3: 2^3 with no 0s, 3*2^2 with one 0, 010, 020, so 22 n = 4: 2^4 no 0s, 4*2^3 one 0, 4 of the form 0*0*, 4 *0*0, and 4 0**0, so 60 This is consistent with the above (e.g., 21 + 60 = 81 = 3^4). And it's easier to count, if we pay attention to how many strings end in 0 or 1. n = 1: 1 ends in 0, 2 don't (3) n = 2: 2 end in 0, 6 don't (8) n = 3: 6 end in 0, 16 don't (22) n = 4: 16 end in 0, 44 don't (60) Now there's a nice pattern: to go to the words one digit longer, you can add a 1 or 2 to a word that ends in 0, and you can add anything to the end a of word that ends in 1 or 2. So if wn = an + bn, where an is the number of lenght n words ending in 0 and bn is the number ending in 1 or 2, then w(n+1) = 2an + 3bn. This matches all the data above. To go on, you actually need formulas for a(n+1) and b(n+1). That's not hard: a(n+1) = bn (the only new words that can end in 0 came from the length n words that didn't end in 0) and b(n+1) = 2an + 2bn (the rest, the length n words that had 1 or 2 put on the end). n...an...bn...wn...3^n - wn 1.....1.....2.....3......0 2.....2.....6.....8......1 3.....6....16...22......5 4....16...44...60......21 5....44..120..164....79 6..120..328..448....281 You might be able to do something directly with 1, 5, 21, 79, 281, but this is what made sense to me.
  

Q.A ball is thrown vertically at time = 0s from a point on a roof 10m above the ground. What is velocity of ball?Related Search:
Physics
 A ball is thrown vertically at time = 0s from a point on a roof 10m above the ground. The initial velocity is 58.5 m/s. At time = 5.97 the velocity of the ball is what?
A.Let: h be the height of the ball above ground. u be its initial speed, v be its speed at time t later, g be the acceleration due to gravity. I take it that the time is 5.97 sec. If the ball is thrown up: v = u - gt = 58.5 - 9.81 * 5.97 = - 0.0657 m/s The speed is 0.0657 m/s downwards. If the ball is thrown down: v = u + gt = 58.5 + 9.81 * 5.97 = 117 m/s to 3 sig. fig. downwards.
  

Q.what is the magnitude of the cart's displacement during the 1st 6.0s of its motion?Related Search:
Physics
 a cart is given an initial velocity of 5.0m/s and experiences a constant acceleration of 2.0m/s^2. what is the magnitude of the carts displacement during the first 6.0s of its motion?
A.equation to use: s = ut +0.5at² s = 5.0*6 + 0.5*2.0*6.0² s = 30 + 36 s = 66m The displacement of the cart will be 66m in the direction of the acceleration.
  

Q.What is the average power output of an elevator that lifts 865 kg a vertical height of 30.0m in 11.0s?Related Search:
Physics
 What is the average power output of an elevator that lifts 865 kg a vertical height of 30.0m in 11.0s? P = __________ W ?
A.Power = work /time Power = 865*9.8*30/11 Power = 23,119W
  

Q.What is the difference between Nike SBs and Nike 6.0s in terms of skating?Related Search:
Other - Sports
 Is there a difference between Nike 6.0s and Nike SBs in terms of skating? Both seem intended for skating...does either brand seem better than the other?
A.i think its mainly because those are probably two subcompanies like coke and coke zero and they are trying to make better things then each other. PS if you want shoes get nike sb zoom air tres. they take a long time to tear
  
 Dictionary Opens New Window.
No definitions found for 0s.

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 Encyclopedia Opens New Window.

For the recent decade, also sometimes called "the 0s", see 2000–2009.
Millennium: 1st millennium
Centuries: 1st century BC1st century2nd century
Decades: 20s BC 10s BC 0s BC0s10s 20s 30s
Years: AD AD AD AD AD AD AD AD AD
Categories: BirthsDeathsArchitecture
EstablishmentsDisestablishments
Eastern Hemisphere at the beginning of the 1st century AD

This article is about the period 1–9 AD, the first nine years of the 1st century and the 1st millennium. Note that there is no year zero (0) in either the proleptic Gregorian calendar or the Julian calendar. Hence AD 1 was preceded by the year 1 BC.

Contents

[edit] Events and trends

[edit] Significant people

[edit] Contemporaries of future importance

[edit] References

  1. ^ The Silkroad Foundation's silk road chronology. Accessed 2009-06-14. Archived 2009-06-17.
  2. ^ a b c Klingaman, William K., The First Century: Emperors, Gods and Everyman, 1990, p 64


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